Asked by Anonymous
What is the standard form of the equation of the parabola that has a vertex at (4, 3) and passes through the point (-4, -2)?
Is it f(x) = -5/64(x - 4)^2 + 3?
Is it f(x) = -5/64(x - 4)^2 + 3?
Answers
Answered by
Reiny
let's test it.
does (-4,-2) satisfy your equation ?
LS = -2
RS = (-5/6)(64) + 3 ≠ -2
Nope!
Looks like you had a good part of it.
the equation must be
y = a(x-4)^2 + 3
plug in (-4,-2)
-2 = a(64) +3
take over, let me know what you got
does (-4,-2) satisfy your equation ?
LS = -2
RS = (-5/6)(64) + 3 ≠ -2
Nope!
Looks like you had a good part of it.
the equation must be
y = a(x-4)^2 + 3
plug in (-4,-2)
-2 = a(64) +3
take over, let me know what you got
Answered by
Anonymous
The equation -2 = a(64) +3 gives 64a = -5, or a = -5/64.
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