Asked by Anonymous

What is the standard form of the equation of the parabola that has a vertex at (4, 3) and passes through the point (-4, -2)?

Is it f(x) = -5/64(x - 4)^2 + 3?

Answers

Answered by Reiny
let's test it.

does (-4,-2) satisfy your equation ?

LS = -2
RS = (-5/6)(64) + 3 ≠ -2

Nope!

Looks like you had a good part of it.

the equation must be
y = a(x-4)^2 + 3
plug in (-4,-2)
-2 = a(64) +3

take over, let me know what you got
Answered by Anonymous
The equation -2 = a(64) +3 gives 64a = -5, or a = -5/64.

Related Questions