Asked by Felix

An aeroplane leave Bibiani at 10:10pm and reaches Accra 4415km away at 5:50am the next morning. Find correct to the nearest whole number the average speed of the aeroplane in km/h.
Answered by oobleck
10:10 PM to 5:10 AM is 7 hours, so the time is 7hr 40 min = 23/3 hours
speed = distance/time, so
4415km / (23/3 hr) = 575.87 km/hr
Answered by lawrence
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Answered by lawrence
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Answered by Rosemond Essoun
575.87km/hr