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Asked by lisa

The slope of the tangent to the curve f(x)= x^3 + x at any point can be given by the expression
1. 3x^2
2. 3x^2 + 1
3. x^3+1
4. x^3
5 years ago

Answers

Answered by Anonymous
d/dx (x^n) = n x^(n-1)
so
3 x^2 + 1 x^0 = 3 x^2 + 1
5 years ago
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The slope of the tangent to the curve f(x)= x^3 + x at any point can be given by the expression
1. 3x^2
2. 3x^2 + 1
3. x^3+1
4. x^3

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