Question
An object moves along a straight path. Its position, S, in meters, at t seconds, is given by s(t)= 2t^2-t/t-1. Determine the average rate of change of the object after 3s/
1. 29/16 m/s
2. 5/16 m/s
3. 5/4 m/s
4. 29/4 m/s
1. 29/16 m/s
2. 5/16 m/s
3. 5/4 m/s
4. 29/4 m/s
Answers
oobleck
since having t/t is kind of dumb, I suspect you meant
s(t) = (2t^2-t)/(t-1). If so, then
(s(3)-s(0))/(3-0) = (15/2 - 0)/3 = 5/2
Hmmm. Maybe you can fix it.
s(t) = (2t^2-t)/(t-1). If so, then
(s(3)-s(0))/(3-0) = (15/2 - 0)/3 = 5/2
Hmmm. Maybe you can fix it.