Asked by monkey
A piece of metal has its temperature raised from 25.0 o C to 55.0 o C. The metal has a mass of 12.5 g. If 338 J of heat is absorbed, what is the specific heat of the metal?
Answers
Answered by
DrBob222
q = mass metal x specific heat metal x (Tfinal - Tintial)
338 = 12.5 x specific heat metal x (55.0 - 25.0)
Solve for specific heat of metal
338 = 12.5 x specific heat metal x (55.0 - 25.0)
Solve for specific heat of metal
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