Ask a New Question

Question

A 0.5kg piece of metal (c = 600/kgK) at 300 degree celcius is dumped into a large pool of water at 20 degrees celcius. Assuming the change in temperature of water to be negligible, calculate the overall change in entropy for the system
12 years ago

Answers

Elena
ΔS =ΔQ/T= cmΔT/T =
=600•0.5•280/20=4200 J/K
12 years ago
Ugonnia
122.3J/k
12 years ago

Related Questions

If a hot piece of metal (at 80 degrees Celsius) is placed in cold water (10 degrees Celsius), what c... A 500 g piece of metal at 60 degrees celsius is placed in 200g of water at 22 degrees celsius contai... If a 10.0 g piece of metal required 100 cal to raise its temperature by 20°C, what would you r... When a 77 g piece of metal with a temperature of 88 Degree Celsius is placed into 277 g of water hav... A 355-g piece of metal at 48.0 degree celsius is dropped into 111g of water at 15.0 degree celsius.I... Consider a piece of metal that is at 5 deg C. If it is heated until it has twice the internal energy... a 5.0 x 10^1g piece of a metal in thermal equilibrium with boiling water is removed and placed in 1.... a .300 kg piece of metal is heated to 88 degrees celsius and placed in a copper calorimeter with a m... A 13.8 g piece of Zn metal was heated to 98.6 oC and then dropped in 45.6 g of water at 25.0 oC. As... If you add a metal piece to excess acid, what of listed factors below will increase, decrease, or ha...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use