Asked by Kim
Use a graphing utility to approximate (to two-decimal-place accuracy) any relative minimum or maximum values of the function.
y=x^3 - 6x^2 + 15
My answer was (4,12) for min and(0,-12) for max.
y=x^3 - 6x^2 + 15
My answer was (4,12) for min and(0,-12) for max.
Answers
Answered by
kellie
y=x+2
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