Asked by Aki
                If Vertex is (4,-7) and x intercept is 4, what is the standard equation of the parabola?
            
            
        Answers
                    Answered by
            oobleck
            
    no calculus need for this. Remember your Algebra I
Vertex is (4,-7) ... y = a(x-4)^2 - 7
But the x-intercept cannot be 4, since we know that y(4) = -7
However, if you meant that the y-intercept is 4, then
a(0-4)^2 - 7 = 7
a = 7/8
and thus
y = 7/8 (x-4)^2 - 7
Now just rearrange that into standard form.
    
Vertex is (4,-7) ... y = a(x-4)^2 - 7
But the x-intercept cannot be 4, since we know that y(4) = -7
However, if you meant that the y-intercept is 4, then
a(0-4)^2 - 7 = 7
a = 7/8
and thus
y = 7/8 (x-4)^2 - 7
Now just rearrange that into standard form.
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.