Asked by kyle
                let f(x) = Sec (x) in the interval 0<x<pie/3. What is the average rate of change of f(x) with respect to x in this interval?
            
            
        Answers
                    Answered by
            Reiny
            
    find f(0) and f(π/3)
avg rate of change = (f(π/3) - f(0))/(π/3-0)
= (2 - 1)/(π/3)
= 3/π
    
avg rate of change = (f(π/3) - f(0))/(π/3-0)
= (2 - 1)/(π/3)
= 3/π
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