Asked by Mike

The different between the 11th term of an AP is 49 and if the 11th term is 74/25 times the 4th term determine ,the common difference ,the first term of the sequence and the 6th term of the sequence
Answered by oobleck
"The difference between the 11th term of an AP is 49"
makes no sense.
difference between T11 and what?

but the second criterion is

a+10d = 74/25 (a+3d)
Answered by Adeoye
The difference between the 11th term and 4th of an A.P is 49 and if the 11th term is 74 times the fourth term determine A the common difference B first term
Answered by Ifunanya
T11-T4=49
a+10d-(a+3d)=49
a+10d-a-3d=49
10d-3d=49
7d=49
d=7

T11=74/25×T4
a+10d = 74/25×a+3d
a+10d=74a+222d
------------------
25

25(a+10d)=74a+222d
25a+250d=74a+222d
25a-74a=222d-250d
-49a=-196
a=4

Where a is first num
d is common difference
6th term = a + 5d
Then substitute
Answered by Anonymous
How did u gett 222d
Answered by Anonymous
74 times 3
Answered by Favour
Favour
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