Asked by Brian
For problems 1 and 2 find y' with respect to t.
1. 2y^2=x^3
2. y=2i+2w
1. 2y^2=x^3
2. y=2i+2w
Answers
Answered by
oobleck
use the chain rule.
2y^2 = x^3
4y dy/dt = 3x^2 dx/dt
dy/dt = (3x^2)/(4y) dx/dt
#2 looks suspiciously like a perimeter (meaning "i" is a typo for "l") since 2i is an imaginary constant.
Same rule applies
dy/dt = 2(dl/dt + dw/dt)
Why do I suspect that there is more to these problems that you have shown?
2y^2 = x^3
4y dy/dt = 3x^2 dx/dt
dy/dt = (3x^2)/(4y) dx/dt
#2 looks suspiciously like a perimeter (meaning "i" is a typo for "l") since 2i is an imaginary constant.
Same rule applies
dy/dt = 2(dl/dt + dw/dt)
Why do I suspect that there is more to these problems that you have shown?
Answered by
Brian
Yes I meant "I"
Answered by
Brian
is the answer 2 for #2?
Answered by
oobleck
huh? If l and w are functions of time t, then they must also be changing, right? So, unless dl/dt + dw/dt =1, the answer is not 2.
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