That's better.
Assuming that AC bisects ∠DAB, then the two halves are equal, right? So
x + x-16 = 66
x = 41
∠CAB = 25°
If I got the angle relationship wrong, then maybe you need to clarify things some.
if the measure of ∠DAB= 66∘, ∠CAB=x, and ∠DAC= x−16, find the measure of ∠CAB
2 answers
What is the measure of the DC