Asked by df

Procedure in preparing solution for 250.0 mL of 0.2500M cupric sulfate solution from anhydrous cupric sulfate. Assume
100% purity.
Answered by bobpursley
moles cupric sulfate= volume*concentrtion=.250*.25= ???

mass copper sulfate= moles above*molarmassCuSO4

I assume you can figure the molar mass of cupric sulfate by yourself.
Answered by DrBob222
mols you want = M x L = 0.25 M x 0.25 L = ?
Then grams = mols CuSO4 x molar mass CuSO4 = ? grams CuSO4
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