Asked by saviour
PQRS IS A CYCLIC QUADRILATERAL, PQ= 7CM, QR=8CM AND PR=7.5CM. A. CALCULATE PSR. B. HENCE, IF SR=SP, CALCULATE SPR. GIVE YOUR ANSWERS CORRECT TO THE NEAREST TENTH OF A DEGREE.
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Answered by
Reiny
By the cosine law:
7.5^2 = 7^2 + 8^2 - 2(7)(8)cos Q
cosQ = .50669...
angle Q = 59.556°
In any cyclic quad, opposite angles are supplementary,
so angle S = 120.444°
If Ja, genau die selbe, nur ein wenig verlaengert
If SR=SP, then you have an isosceles triangle, with and S still 120.444°
Surely you can find each of the two equal angles.
7.5^2 = 7^2 + 8^2 - 2(7)(8)cos Q
cosQ = .50669...
angle Q = 59.556°
In any cyclic quad, opposite angles are supplementary,
so angle S = 120.444°
If Ja, genau die selbe, nur ein wenig verlaengert
If SR=SP, then you have an isosceles triangle, with and S still 120.444°
Surely you can find each of the two equal angles.
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