Asked by Christopher

In a cyclic quadrilateral ABCD twice angle BAD =three times angle DCB. Calculate angle BAD
Answered by Steve
The key here is to recognize that opposite angles are supplementary. So,

BAD+BCD = 180
2BAD=3BCD, so BCD = 2/3 BAD

5/3 BAD = 180
BAD = 108
Answered by Praise
BAD+BCD=180
2BAD=3 BAD,so BCD =2/3BAD
5/3BAD=180
BAD=108
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