Question

In a cyclic quadrilateral ABCD twice angle BAD =three times angle DCB. Calculate angle BAD

Answer 1

The key here is to recognize that opposite angles are supplementary. So,

BAD+BCD = 180
2BAD=3BCD, so BCD = 2/3 BAD

5/3 BAD = 180
BAD = 108

Answer 2

BAD+BCD=180
2BAD=3 BAD,so BCD =2/3BAD
5/3BAD=180
BAD=108