Asked by Daniel

to create a 0.25 M Potassium Chloride solution. Your mass is 5.00 grams of Potassium Chloride. How many liters of water is needed?
Answered by oobleck
how many moles of KCl in 5g? 5/74.55 = 0.067 moles

x/0.067moles = 1000mL/0.25moles
x = 268 mL
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