Asked by Sani

There are 16 boys and 16 girls eligible to swim on a mixed relay. In how many ways could the relay team be chosen if the team must contain 2 boys and 2 girls.
Note: the order of the swimmers on the relay matters.
Answered by oobleck
There are 16C2 ways to choose the girls and the boys.
There are 4! ways to arrange the 4 choices. So,
16C2 * 16C2 * 4! = 120^2 * 24 = 345,600 ways
Answered by Sani
What would the difference be if instead of 16 girls and boys there were 11 or each?
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