Asked by mereula
I have 130 liters of gas in a piston at a temperature of 250 degree Celsius. If i cool the gas until the volume decreases to 85 liters what will temperature of the gas be?
Answers
Answered by
oobleck
what about the pressure?
PV = kT
I guess if you somehow keep the pressure constant, then V/T is constant, so you want T such that
85/T = 130/(250+273.15)
T = 342°K = 69°C
PV = kT
I guess if you somehow keep the pressure constant, then V/T is constant, so you want T such that
85/T = 130/(250+273.15)
T = 342°K = 69°C
Answered by
rhae not ur mum
V1/T1=V2/T2
1.130L = 85L 2. 250*85/130=L 3. 163.5 (1d.p) C and 436.6 K
/250 /T2
you check by 130 /250 to get 0.52. and with the other side 85/163.5 to also get 0.52. since they are both proportionate equations they should both equal one another. The answ also makes sense since if volume decreasing should also make temp decrease :D
1.130L = 85L 2. 250*85/130=L 3. 163.5 (1d.p) C and 436.6 K
/250 /T2
you check by 130 /250 to get 0.52. and with the other side 85/163.5 to also get 0.52. since they are both proportionate equations they should both equal one another. The answ also makes sense since if volume decreasing should also make temp decrease :D
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