Asked by anonymous

Mercury is commonly supplied in flasks containing 34.5 kg (about 76 lb) of the element, which has a density of 13.6 g/cm3. What is the volume, in liters, of this much mercury? correct sig figs
Answered by DrBob222
mass = volume x density.
Substitute the numbers in the problem and solve for volume in cc. Convert to L. Show your work if you get stuck.
Answered by anonymous
do i have to use the 76lbs or could I just use the 34.5kg
Answered by Anonymous
Use 34.5 Kg but it has to be converted to grams. 34.5kg=34500g
Answered by anonymous
ok sounds good. does anyone mind solving it out so that I can check my answer
Answered by anonymous
i got 2.5L is that correct?
Answered by DrBob222
Yes, but the problem states the answer should be to the correct number of significant figures. You have three s.f. in 34.5 kg and 13.6 in g/cc so you can have 3 s.f. in your answer. 2.5 is two places.
Answered by anonymous
oh yeah i forgot so it is 2.54L
Answered by DrBob222
right
Answered by jang jang

m= v•d
34.5 kg= v(13.6 g/cm³)

•derive your equation to get the volume (v):
v= [34.5 kg/ (13.6 g/ cm³)]

•before solving, convert kg to g:
v= [(34, 500 g)/ (13.6 g/ cm³)]
= 2, 536.76 cm³

•covert in liters and round it off:
v= 2.5 L
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