Asked by Leah
If we want to prepare 125 mL of a 1.245 M aqueous KCl solution from a 7.134 M aqueous KCl solution, how many mL of the 7.134 M solution (rounded with correct number of significant figures) will we need to put in the new solution?
Answers
Answered by
DrBob222
The dilution formula is
mL1 x M1 = mL2 x M2
mL1 x 7.134M = 125 x 1.245
Solve for mL1 = ?
mL1 x M1 = mL2 x M2
mL1 x 7.134M = 125 x 1.245
Solve for mL1 = ?
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