Asked by Julie
how would you prepare 250 mL of a .1 M C12H22O11 starting with 2.5M C12H22O11
Answers
Answered by
DrBob222
I would use the dilution formula of
c1v1 = c2v2.
c = concn
v = volume
Plug in the numbers.
c1v1 = c2v2.
c = concn
v = volume
Plug in the numbers.
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