Asked by jer
Sorry I have another question, but it's a true/false question and it's asking
"if Lim x->5 (m(x)-m(5))/(x-5) = -3, then m(x) is continuous at x=5."
Can't there be a hole, so would it be false?
"if Lim x->5 (m(x)-m(5))/(x-5) = -3, then m(x) is continuous at x=5."
Can't there be a hole, so would it be false?
Answers
Answered by
oobleck
correct. m(5) must be defined and equal to the limit.
Answered by
Damon
looks like [ m(5+e) - m(5) ] / ( x-5) = -3 as e--->0
looks like the derivative dm/dx = -3 at x = 5
If we can define a unique derivative(slope) there, m better be continuous there.
Sketch graphs of these problems :)
looks like the derivative dm/dx = -3 at x = 5
If we can define a unique derivative(slope) there, m better be continuous there.
Sketch graphs of these problems :)
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