Asked by Anonymous
Using first principle in calculus.solve
2x²+5x+3
2x²+5x+3
Answers
Answered by
oobleck
solve what? There is no equation.
But, since your subject is calculus, I assume you want the derivative.
If f(x) = 2x^2 + 5x + 3, then
f(x+h) = 2(x+h)^2 + 5(x+h) + 3
and df/dx is the limit as h→0 of
(2(x+h)^2 + 5(x+h) + 3 - (2x^2+5x+3))/h
= (4hx + 2h^2 + 5h)/h
= 4x + 5 + 2h
→ 4x+5
But, since your subject is calculus, I assume you want the derivative.
If f(x) = 2x^2 + 5x + 3, then
f(x+h) = 2(x+h)^2 + 5(x+h) + 3
and df/dx is the limit as h→0 of
(2(x+h)^2 + 5(x+h) + 3 - (2x^2+5x+3))/h
= (4hx + 2h^2 + 5h)/h
= 4x + 5 + 2h
→ 4x+5
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