Asked by Sébastien
Need help for calcul:
( 1/2 ( -1 + i√3 )) ^2
thanks for your help
( 1/2 ( -1 + i√3 )) ^2
thanks for your help
Answers
Answered by
drwls
That can be rewritten
(1/2)^2 * (-1 + i√3)^2
= (1/4)[1 -2i√3 -3]
= (-1/2)[1 +i√3]
(1/2)^2 * (-1 + i√3)^2
= (1/4)[1 -2i√3 -3]
= (-1/2)[1 +i√3]
Answered by
drwls
Note that you are squaring a complex number that has a magnitude (modulus) of 1.
The number that is being squared can be written
e^(i*2*pi/3) = cos(2*pi/3) + i sin(2*pi/3)
The square of that number is e^(i*4*pi/3)
which agrees with the previous result.
The number that is being squared can be written
e^(i*2*pi/3) = cos(2*pi/3) + i sin(2*pi/3)
The square of that number is e^(i*4*pi/3)
which agrees with the previous result.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.