Asked by jay

A tennis ball with a speed of 15.1 m/s is
moving perpendicular to a wall. After striking
the wall, the ball rebounds in the opposite
direction with a speed of 7.9577 m/s.
If the ball is in contact with the wall for
0.0139 s, what is the average acceleration of
the ball while it is in contact with the wall?
Take “toward the wall” to be the positive
direction.
Answer in units of m/s^2.

Answers

Answered by R_scott
acceleration equals ... Δv / t = (15.1 - -7.9577) / .0139

watch your significant figures

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