CH3COOH <<<< that H is a proton
CH3COO- <<<< that proton left.
H3O+ Oh, there it is !
What chemical equation represents the ability of a substance to donate a proton in water?
A. NH3 + H2O <-> NH4+ + OH-
B. CH3COOH + H2O <-> CH3COO- + H3O+
C. CH4 + 2O2 --> CO2 + H2O
D. CH3COOH + NaOH <-> CH3COOH + NaCl
I think the answer has to be either A or B. It can't be D because Cl is randomly introduced and C isn't a reaction in water. Can you guys help me our please.
3 answers
So is the answer B?
Yes, the answer is B. The H from the -COOH group donates a proton to H2O to make the H2O become H3O^+ (the hydronium ion)
As Damon points out you should see that the CH3COOH on the left is missing the on on the right to become CH3COO- and the H2O on the right shows the H2O has been added to become H3O^+.
As Damon points out you should see that the CH3COOH on the left is missing the on on the right to become CH3COO- and the H2O on the right shows the H2O has been added to become H3O^+.
2 answers