Asked by Bob
I need help on math 7 a Lesson 4: Adding and Subtracting Rational Numbers
Essential Math 7 A Unit 4: Operations with Fractions Quiz.
Essential Math 7 A Unit 4: Operations with Fractions Quiz.
Answers
Answered by
Bob
its at connexcus btw
Answered by
Bob
May someone respawn to me please!
Answered by
Bob
7th grade
Answered by
help please
Most authors use which point of view in an informational text?(1 point)
a subjective
b connotative
c first-person
d objective
a subjective
b connotative
c first-person
d objective
Answered by
DrBob222
We don't have the lessons to which you refer us.
Answered by
goldenfreddy39
Bob (not teacher bob) Use a calculator and your book
Answered by
javarious
need help
Answered by
Annora Beatrice Monrrow
I don't know if you're going to see this but pearson is hard and its my last year in middle and you should try kahan Academy it really helps me, understand a lesson on peason.
Answered by
im gonna hit the whoa on ur hairline B)
give the question and answers
Answered by
Answers for Connexus Students
1. A or -1/6
2. D or -9 and 7/10
3. D or 7/8
4. A or -1 and 3/10
5. D or 8 and 4/5
There are the answers u people are begging for
also it is lesson 4.4.7 on connexus
2. D or -9 and 7/10
3. D or 7/8
4. A or -1 and 3/10
5. D or 8 and 4/5
There are the answers u people are begging for
also it is lesson 4.4.7 on connexus
Answered by
nova
1: A
2: C
3: D
4: A
5: B
100% right checked it myself
2: C
3: D
4: A
5: B
100% right checked it myself
Answered by
mom
nova is wrong i got 60% thanks a lot. :( T-T
Thanks Answers for connexus for the right answers i wish i wouldve used them
Thanks Answers for connexus for the right answers i wish i wouldve used them
Answered by
the box
here are all the answers
1: D
2: A
3: A
4: C
5: A
100% trust me
1: D
2: A
3: A
4: C
5: A
100% trust me
Answered by
lol kd
omg thanks
Answered by
pie
TYSM
Answered by
Y LIFE
100% hes right 100%
Answered by
ok
the answers are
1.A
2.D
3.D
4.A
5.D
trust me the other answers are wrong
1.A
2.D
3.D
4.A
5.D
trust me the other answers are wrong
Answered by
Me
there is 8 for me???
Answered by
HELP PLEASE!!!
doe anybody have the answers to the math 7A lesson 5 property shmoperties quiz please i really need the help
Answered by
hi
there is 8 for me to
Answered by
Merry Chrysler
Adding and Subtracting Rational Numbers Quick Check:
A
D
D
A
D
A
D
D
A
D
Answered by
Kathryn Jackson
1.A
2.C.
3.D
4.A
5.B
01/02/21
2.C.
3.D
4.A
5.B
01/02/21
Answered by
prezily offical
STOP CHEETING
Answered by
CONNEXUS STUDENT
There are 30 for me LOL
Answered by
Harrypotterfreak
Bloody Hell, thankyou so much Kathryn. I got a 100% percent thanks to you ;)
Answered by
Balony.
Mr prezily offical,
Why are you here then O_o hm? OH i KNOW WHY!!!!! because you're here looking for answers as well :l so i dont know what u r complaining about. You're here to. So dont complain and tell us not to cheat. I STUDY HERE with my CLASSMATES not CHEAT LIKE U :V
Why are you here then O_o hm? OH i KNOW WHY!!!!! because you're here looking for answers as well :l so i dont know what u r complaining about. You're here to. So dont complain and tell us not to cheat. I STUDY HERE with my CLASSMATES not CHEAT LIKE U :V
Answered by
Anonymous
There randomized
Answered by
error
Love you
Answered by
6foot under
f^2 x f^3
Answered by
Bot
f^5, because when you have the same base and you're multiplying exponents, you add the exponents. In this case, f has an exponent of 2 and an exponent of 3, so 2+3=5.
Answered by
6foot under
100^12
100^8
100^8
Answered by
Bot
To simplify 100^12, you multiply 100 by itself 12 times, which is equal to 100,000,000,000,000,000,000,000.
For 100^8, you multiply 100 by itself 8 times, which is equal to 100,000,000.
For 100^8, you multiply 100 by itself 8 times, which is equal to 100,000,000.
Answered by
6foot under
100^12
_____
100^8
_____
100^8
Answered by
Bot
To divide these two powers with the same base (100), you can subtract the exponent of the denominator from the exponent of the numerator:
100^12 / 100^8 = 100^(12-8) = 100^4
Therefore, the simplified form of 100^12 / 100^8 is 100^4.
100^12 / 100^8 = 100^(12-8) = 100^4
Therefore, the simplified form of 100^12 / 100^8 is 100^4.
Answered by
6foot under
x^16
___
x^3
___
x^3
Answered by
6foot under
x^16 divided by x^3
Answered by
Bot
When you divide two like bases with exponents, you can subtract the exponent in the denominator from the exponent in the numerator.
In this case, x is the base and the exponent in the numerator is 16 and the exponent in the denominator is 3. Therefore:
x^16 / x^3 = x^(16-3) = x^13
So, the simplified form of x^16 / x^3 is x^13.
In this case, x is the base and the exponent in the numerator is 16 and the exponent in the denominator is 3. Therefore:
x^16 / x^3 = x^(16-3) = x^13
So, the simplified form of x^16 / x^3 is x^13.
Answered by
6foot under
which following expression
4^3 x 4^5 < 4^12
5^2 x 5^3 > 5^5
3^2 x 3^4 = 3^2
5^2 x 5^4 = 5^8
4^3 x 4^5 < 4^12
5^2 x 5^3 > 5^5
3^2 x 3^4 = 3^2
5^2 x 5^4 = 5^8
Answered by
Bot
The correct inequality is `4^3 x 4^5 < 4^12`. This can be simplified to `4^8 < 4^12`, which is true since 4^8 is less than 4^12.
The correct inequality is `5^2 x 5^3 < 5^5`. This can be simplified to `5^5 < 5^5`, which is false since 5^5 is equal to 5^5, not less than it.
The correct equation is `3^2 x 3^4 = 3^6`. This is true because when you multiply two like bases, you add the exponents. In this case, 2+4=6, so `3^2 x 3^4 = 3^6`.
The correct equation is `5^2 x 5^4 = 5^6`. This is true because when you multiply two like bases, you add the exponents. In this case, 2+4=6, so `5^2 x 5^4 = 5^6`.
The correct inequality is `5^2 x 5^3 < 5^5`. This can be simplified to `5^5 < 5^5`, which is false since 5^5 is equal to 5^5, not less than it.
The correct equation is `3^2 x 3^4 = 3^6`. This is true because when you multiply two like bases, you add the exponents. In this case, 2+4=6, so `3^2 x 3^4 = 3^6`.
The correct equation is `5^2 x 5^4 = 5^6`. This is true because when you multiply two like bases, you add the exponents. In this case, 2+4=6, so `5^2 x 5^4 = 5^6`.
Answered by
6foot under
which following expressions is true?
4^3 x 4^5 < 4^12
5^2 x 5^3 > 5^5
3^2 x 3^4 = 3^2
5^2 x 5^4 = 5^8
4^3 x 4^5 < 4^12
5^2 x 5^3 > 5^5
3^2 x 3^4 = 3^2
5^2 x 5^4 = 5^8
Answered by
Bot
The true expression is `4^3 x 4^5 < 4^12`.
To simplify this expression:
- `4^3` is equal to 64 since 4 multiplied by itself three times equals 64.
- `4^5` is equal to 1,024 since 4 multiplied by itself five times equals 1,024.
- `4^12` is equal to 167,772,16 since 4 multiplied by itself 12 times equals 167,772,16.
So we can rewrite the inequality as:
64 x 1,024 < 167,772,16
When we multiply 64 and 1,024 we get 65,536, which is indeed less than the value of `4^12`, so the inequality is true.
To simplify this expression:
- `4^3` is equal to 64 since 4 multiplied by itself three times equals 64.
- `4^5` is equal to 1,024 since 4 multiplied by itself five times equals 1,024.
- `4^12` is equal to 167,772,16 since 4 multiplied by itself 12 times equals 167,772,16.
So we can rewrite the inequality as:
64 x 1,024 < 167,772,16
When we multiply 64 and 1,024 we get 65,536, which is indeed less than the value of `4^12`, so the inequality is true.
Answered by
6foot under
which of the following expression is true?
2^4 x 2^3 = 2^12
3^3 x 3^6 > 3^8
4^2 x 4^2 > 4^4
5^5 x 5^2 = 5^10
2^4 x 2^3 = 2^12
3^3 x 3^6 > 3^8
4^2 x 4^2 > 4^4
5^5 x 5^2 = 5^10
Answered by
Bot
The true expression is `2^4 x 2^3 = 2^7`.
When you multiply two like bases, you add the exponents. In this case, `2^4` is equal to 16, and `2^3` is equal to 8, so `2^4 x 2^3` is equal to `16 x 8`, which is equal to 128, or `2^7`.
Therefore, the expression `2^4 x 2^3 = 2^7` is true.
When you multiply two like bases, you add the exponents. In this case, `2^4` is equal to 16, and `2^3` is equal to 8, so `2^4 x 2^3` is equal to `16 x 8`, which is equal to 128, or `2^7`.
Therefore, the expression `2^4 x 2^3 = 2^7` is true.
Answered by
6foot under
write the value of the equation
4^5 divided by 4^5
4^5 divided by 4^5
Answered by
Bot
The value of `4^5 divided by 4^5` is 1.
When you divide two like bases with exponents, you can subtract the exponent in the denominator from the exponent in the numerator.
In this case, `4` is the base and the exponent in the numerator is 5, and the exponent in the denominator is also 5. So:
`4^5 / 4^5` can be simplified to `4^(5-5)`, which is `4^0`.
Any number (except for 0) raised to the power of 0 is equal to 1. Therefore, the value of `4^5 / 4^5` is 1.
When you divide two like bases with exponents, you can subtract the exponent in the denominator from the exponent in the numerator.
In this case, `4` is the base and the exponent in the numerator is 5, and the exponent in the denominator is also 5. So:
`4^5 / 4^5` can be simplified to `4^(5-5)`, which is `4^0`.
Any number (except for 0) raised to the power of 0 is equal to 1. Therefore, the value of `4^5 / 4^5` is 1.
Answered by
6foot under
2^2 divided by 2^5
Answered by
Bot
To divide two like bases with exponents, you can use the rule where you subtract the exponent in the denominator from the exponent in the numerator.
In this case, `2` is the base, and the exponent in the numerator is `2`, and the exponent in the denominator is `5`. So `2^2 / 2^5` can be simplified as follows:
`2^2 / 2^5 = 2^(2-5) = 2^(-3)`
The negative exponent means that the base is in the denominator. So the value of `2^2 / 2^5` is `1/2^3` or `1/8`.
In this case, `2` is the base, and the exponent in the numerator is `2`, and the exponent in the denominator is `5`. So `2^2 / 2^5` can be simplified as follows:
`2^2 / 2^5 = 2^(2-5) = 2^(-3)`
The negative exponent means that the base is in the denominator. So the value of `2^2 / 2^5` is `1/2^3` or `1/8`.
Answered by
6foot under
(2.3 x 10^1)(7 x 10^6)
Answered by
Bot
To multiply two numbers in scientific notation, you can multiply their coefficients and add their exponents.
Using this rule, we can multiply `(2.3 x 10^1)(7 x 10^6)` as follows:
`(2.3 x 10^1)(7 x 10^6) = (2.3 x 7) x 10^(1+6)`
`= 16.1 x 10^7`
So `(2.3 x 10^1)(7 x 10^6)` is equal to `16.1 x 10^7` in scientific notation.
Using this rule, we can multiply `(2.3 x 10^1)(7 x 10^6)` as follows:
`(2.3 x 10^1)(7 x 10^6) = (2.3 x 7) x 10^(1+6)`
`= 16.1 x 10^7`
So `(2.3 x 10^1)(7 x 10^6)` is equal to `16.1 x 10^7` in scientific notation.
Answered by
6foot under
(1.1 x 10^-5)(3 x 10^-2)
Answered by
Bot
To multiply two numbers in scientific notation, multiply their coefficients and add their exponents.
Using this rule, we can multiply `(1.1 x 10^-5)(3 x 10^-2)` as follows:
`(1.1 x 10^-5)(3 x 10^-2) = (1.1 x 3) x 10(-5-2)`
`= 3.3 x 10^-7`
So `(1.1 x 10^-5)(3 x 10^-2)` is equal to `3.3 x 10^-7` in scientific notation.
Using this rule, we can multiply `(1.1 x 10^-5)(3 x 10^-2)` as follows:
`(1.1 x 10^-5)(3 x 10^-2) = (1.1 x 3) x 10(-5-2)`
`= 3.3 x 10^-7`
So `(1.1 x 10^-5)(3 x 10^-2)` is equal to `3.3 x 10^-7` in scientific notation.
Answered by
6foot under
7t^4 x 7t^4
Answered by
Bot
To multiply two monomials with the same base, you keep the base and add the exponents.
In this case, the monomials are `7t^4` and `7t^4`. Since both monomials have the same base (`7t^4`), you can multiply them as follows:
`7t^4 x 7t^4 = (7 x 7) x (t^4 x t^4)`
`= 49 x t^(4+4)`
`= 49t^8`
So `7t^4 x 7t^4` simplifies to `49t^8`.
In this case, the monomials are `7t^4` and `7t^4`. Since both monomials have the same base (`7t^4`), you can multiply them as follows:
`7t^4 x 7t^4 = (7 x 7) x (t^4 x t^4)`
`= 49 x t^(4+4)`
`= 49t^8`
So `7t^4 x 7t^4` simplifies to `49t^8`.
Answered by
6foot under
-x(7x-8)
Answered by
Bot
To multiply `-x(7x-8)`, you need to distribute `-x` to each term inside the parentheses.
So:
`-x(7x-8) = -x * 7x + (-x) * (-8)`
`= -7x^2 + 8x`
Therefore, `-x(7x-8)` simplifies to `-7x^2 + 8x`.
So:
`-x(7x-8) = -x * 7x + (-x) * (-8)`
`= -7x^2 + 8x`
Therefore, `-x(7x-8)` simplifies to `-7x^2 + 8x`.
Answered by
6foot under
3k^2(-2k^2-4k+7
Answered by
Bot
To multiply `3k^2(-2k^2-4k+7)`, you will need to distribute the `3k^2` to each term inside the parentheses.
So:
`3k^2(-2k^2-4k+7) = 3k^2*(-2k^2) + 3k^2*(-4k) + 3k^2*(7)`
`= -6k^4 - 12k^3 + 21k^2`
Therefore, `3k^2(-2k^2-4k+7)` simplifies to `-6k^4 - 12k^3 + 21k^2`.
So:
`3k^2(-2k^2-4k+7) = 3k^2*(-2k^2) + 3k^2*(-4k) + 3k^2*(7)`
`= -6k^4 - 12k^3 + 21k^2`
Therefore, `3k^2(-2k^2-4k+7)` simplifies to `-6k^4 - 12k^3 + 21k^2`.
Answered by
6foot under
(3k + 2)(k - 3)
Answered by
Bot
To multiply `(3k + 2)(k - 3)`, you can use the FOIL method which stands for:
- First: multiply the first terms in each set of parentheses
- Outer: multiply the two terms on the outside (the first term in the first set of parentheses and the second term in the second set of parentheses)
- Inner: multiply the two terms on the inside (the second term in the first set of parentheses and the first term in the second set of parentheses)
- Last: multiply the last terms in each set of parentheses
So:
`(3k + 2)(k - 3) = 3k * k + 3k * (-3) + 2 * k + 2 * (-3)`
`= 3k^2 - 9k + 2k - 6`
`= 3k^2 - 7k - 6`
Therefore, `(3k + 2)(k - 3)` simplifies to `3k^2 - 7k - 6`.
- First: multiply the first terms in each set of parentheses
- Outer: multiply the two terms on the outside (the first term in the first set of parentheses and the second term in the second set of parentheses)
- Inner: multiply the two terms on the inside (the second term in the first set of parentheses and the first term in the second set of parentheses)
- Last: multiply the last terms in each set of parentheses
So:
`(3k + 2)(k - 3) = 3k * k + 3k * (-3) + 2 * k + 2 * (-3)`
`= 3k^2 - 9k + 2k - 6`
`= 3k^2 - 7k - 6`
Therefore, `(3k + 2)(k - 3)` simplifies to `3k^2 - 7k - 6`.
Answered by
6foot under
(-y+4)(2y-1)
Answered by
Bot
To multiply `(-y + 4)(2y - 1)`, you can again use the FOIL method:
- First: Multiply the first term of each expression: `-y * 2y = -2y^2`
- Outer: Multiply the outer two terms: `-y * -1 = y`
- Inner: Multiply the inner two terms: `4 * 2y = 8y`
- Last: Multiply the last term of each expression: `4 * -1 = -4`
Putting it all together:
`(-y + 4)(2y - 1) = -2y^2 + y + 8y - 4 = -2y^2 + 9y - 4`
Therefore, `(-y + 4)(2y - 1)` simplifies to `-2y^2 + 9y - 4`.
- First: Multiply the first term of each expression: `-y * 2y = -2y^2`
- Outer: Multiply the outer two terms: `-y * -1 = y`
- Inner: Multiply the inner two terms: `4 * 2y = 8y`
- Last: Multiply the last term of each expression: `4 * -1 = -4`
Putting it all together:
`(-y + 4)(2y - 1) = -2y^2 + y + 8y - 4 = -2y^2 + 9y - 4`
Therefore, `(-y + 4)(2y - 1)` simplifies to `-2y^2 + 9y - 4`.