Cu = 63.5 g/mol
Fe = 56 g/mol
2 S = 32 *2 = 64 g/ mol
so
CuFeS2 = 63.5 + 56 + 64 grams/ mol of CuFeS2
so if 100 % yield
(63.5+56+64) grams CuFeS2 for 63.5 grams Cu
so
(63.5+56+64 ) / ( 0.82* 63.5)
Calculate the mass of CuFeS2 needed in g to produce 600.0 g Cu if the yield for the conversion process is 82%.
2 answers
Damon, I think your calculation is to produce 1 g Cu. Multiply by 600 to produce 600 grams as per the problem.