Question

so im really stuck on this limit problem. I think it would be ne
lim (2x-1)/(lxl-3)
x-> infinity (and also negative infinity)

Answer 1

oops i accidentally submitted it. I meant to finish it by saying would it not exist for either of them?

Answer 2

for x>0, (2x-1)/(|x|-3) = (2x-1)/(x-3) → 2
for x<0, (2x-1)/(|x|-3) = (2x-1)/(-x-3) → -2
Review the actual definition of |x|

Go to wolframalpha.com and type in your function to see the graph.

Answer 3

ohhh ok. Wow I can't believe I didn't get that. Thank you so much!! :)