Asked by Mikayla
Members of a hospital advisory committee will be selected from 5 doctors and 4 nurses. The committee must have 2 doctors and 2 nurses.
How many possible combinations of doctors and nurses could be chosen for the committee????
How many possible combinations of doctors and nurses could be chosen for the committee????
Answers
Answered by
Damon
7 people
5 Doctors taken 2 at a time
C(5,2) = 5! / [ 2! (5-2)! ] = (5*4* 3) / 3*2 = 10 combinations of doctors
4 nurses, 2 at a time
C(4,2) = 4!/ [ 2! * 2!]= 4*3*2 / 4 = 6
6*10 = 60
5 Doctors taken 2 at a time
C(5,2) = 5! / [ 2! (5-2)! ] = (5*4* 3) / 3*2 = 10 combinations of doctors
4 nurses, 2 at a time
C(4,2) = 4!/ [ 2! * 2!]= 4*3*2 / 4 = 6
6*10 = 60
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