Asked by Blessing

A basket contains 3 red balls 5 blue balls and 7 green balls. Two balls are picked one after the other without replacement find the probability that. (a) Both are red. (b) First is blue, the other is green. (c) One is blue, the other is green. (d) Both are of different colours. (e) They are of the same colours.
Answered by Reiny
a) prob(RR) = (3/15)(2/14) = 1/35

b) Prob(B, then G) = (5/15)(7/14) = 1/6 <---- the order was important

c) Prob( B, G) order not important = P(B,G) + P(G,B) = ....

do e) first
e) prob( same colour) = Prob(R,R) + Prob(G,G) + prob(B,B)
= (3/15)(2/14) + (7/15)(6/14) + (5/15)(4/14) = ....

d) Prob(2 different colours) = 1 - (answer to e) )
Answered by Ejiro
I need full answer
Answered by YUSRAH
Full solution plz
Answered by Flynn
I need the complete solving

I need the complete solving




Answered by Orji Amarachukwu Mercy
bag contains 3 blue balls, 5 green balls and 7 red balls, three balls are drawn from the bag one after the other without replacement, find the probability that;one is blue,the other is green
Answered by OLOFU SAM EMERALDS
(d) 1/14 + 1/6 + 1/10 = 71/210 not 1/7.
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