a basket contains 3 red balls,5 blue balls,&7 green balls.2 balls r picked one after d other without replacement.find d probability that first is blue d other is green

User Icon for PsyDAG PsyDAG answered
3 years ago

It would help if you proofread your questions before you posted them. What is "d"?

5/17 * 7/16 = ?

User Icon for Step-by-Step Bot Step-by-Step Bot answered
1 year ago

To find the probability that the first ball chosen is blue and the second ball chosen is green, we can use the concept of conditional probability.

Step 1: Determine the total number of balls in the basket:
Total number of balls = Number of red balls + Number of blue balls + Number of green balls
Total number of balls = 3 + 5 + 7 = 15

Step 2: Determine the probability of selecting a blue ball:
Probability of selecting a blue ball = Number of blue balls / Total number of balls
Probability of selecting a blue ball = 5 / 15 = 1/3

Step 3: Since we are choosing the balls one after the other without replacement, the second ball will be chosen from a reduced pool of balls. After selecting a blue ball in the first draw, there will be:
Total number of balls left = Total number of balls - 1
Total number of balls left = 15 - 1 = 14

Step 4: Determine the probability of selecting a green ball as the second ball, given that the first ball selected was blue:
Probability of selecting a green ball after selecting a blue ball = Number of green balls / Total number of balls left
Probability of selecting a green ball after selecting a blue ball = 7 / 14 = 1/2

Step 5: Multiply the probabilities from steps 2 and 4 to find the final probability:
Probability of selecting a blue ball and then a green ball = Probability of selecting a blue ball × Probability of selecting a green ball after selecting a blue ball
Probability of selecting a blue ball and then a green ball = (1/3) × (1/2)
Probability of selecting a blue ball and then a green ball = 1/6

Therefore, the probability that the first ball chosen is blue and the second ball chosen is green is 1/6.

User Icon for Explain Bot Explain Bot answered
11 months ago

To find the probability that the first ball picked is blue and the second ball picked is green, we need to calculate two probabilities: the probability of picking a blue ball first, and the probability of picking a green ball given that a blue ball has already been picked.

Let's start with the probability of picking a blue ball first.

Step 1: Calculate the total number of balls in the basket. In this case, there are 3 red balls, 5 blue balls, and 7 green balls, so the total number of balls is 3 + 5 + 7 = 15.

Step 2: Calculate the probability of picking a blue ball first. Since there are 5 blue balls out of a total of 15 balls, the probability of picking a blue ball first is 5/15.

Now, let's move on to the probability of picking a green ball given that a blue ball has already been picked (without replacement).

Step 3: Calculate the updated total number of balls after a blue ball has been picked. Since we are picking without replacement, the total number of balls decreases by 1. So, after a blue ball has been picked, the total number of balls becomes 15 - 1 = 14.

Step 4: Calculate the updated number of green balls after a blue ball has been picked. Since there were originally 7 green balls and we have already picked one ball (which was blue), the number of green balls remaining is 7 - 1 = 6.

Step 5: Calculate the probability of picking a green ball given that a blue ball has already been picked. The probability of picking a green ball in this scenario is 6/14 since there are 6 green balls remaining out of a total of 14 balls.

Step 6: Multiply the probabilities from Steps 2 and 5 to find the probability of picking a blue ball first and then a green ball:
(5/15) * (6/14) = 30/210 = 1/7

Therefore, the probability that the first ball picked is blue and the second ball picked is green is 1/7.