Asked by Anonymous

A man cycled from the market to his house at an average speed of 6 km per hour.If he left the market at 4 0'clock pm and reached his house at 5.15pm how far is his house from the market.
Answered by henry2,
T = 5:15-4:00 = 1hr, 15 min. = 1.25 h.
d = r*T = 6*1.25 =
Answered by Gd dis
I don't understand
the solution
Answered by dream
i dont understand ask another one
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