Asked by Israel
In trangle abc a=29,b=36,b=15.8cm find a. thank you
Answers
Answered by
Israel
Please solve.the question
Answered by
Damon
Please check what you typed. You have two sides called b.
Answered by
oobleck
since you specify that b=15.8 cm, I assume that you meant angles
A=29° and B=36°
If so, then use the law of sines to get
a/sinA = b/sinB
You need to pay attention to your labels. The triangle is usually named by its angles, in Upper Case.
A=29° and B=36°
If so, then use the law of sines to get
a/sinA = b/sinB
You need to pay attention to your labels. The triangle is usually named by its angles, in Upper Case.
Answered by
Damon
If it is angle A you want and c = 15.8 then
a*2 = 841
b^2 = 1296
c^2 = 249.64
a^2 = b^2 + c^2 - 2 b c cos A (law of cosines)
841 = 1296 + 249.64 - 2 * 36 * 15.8 cos A
a*2 = 841
b^2 = 1296
c^2 = 249.64
a^2 = b^2 + c^2 - 2 b c cos A (law of cosines)
841 = 1296 + 249.64 - 2 * 36 * 15.8 cos A
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