Asked by Kaur
Range of 1/[root(x^2-4)]
Answers
Answered by
oobleck
you need x^2-4 > 0 for the domain
So the range is y > 0, or (0,∞)
So the range is y > 0, or (0,∞)
Answered by
Kaur
I got the x in terms of y
And its y=root[(1+4y^2)/y^2]
Its range should not be (- infinity ,+ infinity)
And its y=root[(1+4y^2)/y^2]
Its range should not be (- infinity ,+ infinity)
Answered by
Kaur
Sorry its
x=root[(1+4y^2)/y^2]
f^-1(y)=root[(1+4y^2)/y^2]
f^-1(x)=root[(1+4x^2)/x^2 ]
Where (1+4x^2)/x^2>=0
This inequality is true for any real values of x. So, its range should not be (- infinity ,+ infinity)
Kindly check my solution again
x=root[(1+4y^2)/y^2]
f^-1(y)=root[(1+4y^2)/y^2]
f^-1(x)=root[(1+4x^2)/x^2 ]
Where (1+4x^2)/x^2>=0
This inequality is true for any real values of x. So, its range should not be (- infinity ,+ infinity)
Kindly check my solution again
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