Asked by Lucky
solve 3u_5v=_11 and 2u+7v=3 using elimination method
Answers
Answered by
oobleck
I'm assuming that _ means -, since they are on the same key, so you have
3u-5v = -11
2u+7v = 3
To eliminate y, do
21u-35v = -77
10u+35v = 15
and add to get
31u = -62
Now finish it off
3u-5v = -11
2u+7v = 3
To eliminate y, do
21u-35v = -77
10u+35v = 15
and add to get
31u = -62
Now finish it off
Answered by
henry2,
3u-5v = -11
2u+7v = 3
Multiply Eq1 by 2 and Eq2 by 3; then subtract Eq2 from Eq1:
6u-10v = -22
6u+21v = 9
Diff: -31v = -31
V = 1.
In Eq1, replace v with 1; and solve for u.
2u+7v = 3
Multiply Eq1 by 2 and Eq2 by 3; then subtract Eq2 from Eq1:
6u-10v = -22
6u+21v = 9
Diff: -31v = -31
V = 1.
In Eq1, replace v with 1; and solve for u.
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