A bacteria has a doubling period of 8 days. If there are 2900 bacteria present now, how many will there be in 20 days?

Question

First we must find the daily growth rate (Round this to four decimal places).
The growth rate is
.
Then we use this rate to answer the question.
There will be
bacteria

Answer 1

step by step

Answer 2

"A bacteria has a doubling period of 8 days. If there are 2900 bacteria present now"
-----> count = 2900(2)^(t/8) , where t is number of days

replace t with 20 and start pushing buttons on your calculator

Answer 3

the daily growth factor is 2^(1/8) = 1.0905
That means a daily growth rate of 9.05%