Asked by Maya
A bacteria has a doubling period of 8 days. If there are 2900 bacteria present now, how many will there be in 20 days?
First we must find the daily growth rate (Round this to four decimal places).
The growth rate is
.
Then we use this rate to answer the question.
There will be
bacteria
First we must find the daily growth rate (Round this to four decimal places).
The growth rate is
.
Then we use this rate to answer the question.
There will be
bacteria
Answers
Answered by
Maya
step by step
Answered by
Reiny
"A bacteria has a doubling period of 8 days. If there are 2900 bacteria present now"
-----> count = 2900(2)^(t/8) , where t is number of days
replace t with 20 and start pushing buttons on your calculator
-----> count = 2900(2)^(t/8) , where t is number of days
replace t with 20 and start pushing buttons on your calculator
Answered by
oobleck
the daily growth factor is 2^(1/8) = 1.0905
That means a daily growth rate of 9.05%
That means a daily growth rate of 9.05%
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