a bag contains 6 red tiles and 15 yellow tiles. remove 2 red tiles. How many yellow tiles should she remove so that the ratio of red tiles to yellow tiles in the bag stays equivalent to 6:15? show me

would this be the same as if I remove 2 red, than comes back an remove the same amount from the 15 like remove 2 yellow to equal out the same as the first set of tiles?

So we are supposed to remove 2 red from the 6 red, and x yellow from the 15 yellow so that

4/(15-x) = 6/15
60 = 90 - 6x
6x = 30
x = 5

check:
the original ratio was 6/15 = 2/5
the new ratio is (6-2)/(15-5) = 4/10 = 2/5

i m so confused with this question

I know right!

The answer is 10

The answer is 10. If you don’t believe me then your helpless.

To solve this problem, we need to maintain the ratio of red tiles to yellow tiles as 6:15 when two red tiles are removed from the bag.

Let's start by finding the new number of red tiles in the bag after two are removed. Initially, there are 6 red tiles, so after removing two, there will be 6 - 2 = 4 red tiles left.

Next, we have to determine how many yellow tiles should be removed so that the ratio of red to yellow tiles remains 6:15.

The ratio of red to yellow tiles is currently 4:15 (as there are 4 red and 15 yellow tiles). To maintain the ratio at 6:15, we need to increase the number of red tiles by 2 and the number of yellow tiles by some amount.

The ratio can be expressed as (4 + 2):(15 + x), where x represents the number of yellow tiles to be removed.

Since the ratio of red to yellow tiles should remain the same, the ratio (4 + 2):(15 + x) should be equal to 6:15. Hence, we can set up the following equation:

(4 + 2)/(15 + x) = 6/15

Now, we can solve for x:

(6)/(15) = (4 + 2)/(15 + x)

6(15 + x) = 15(4 + 2)

90 + 6x = 90

6x = 0

x = 0

According to the calculations, no yellow tiles need to be removed to maintain the ratio of 6:15 after removing 2 red tiles.