Asked by Cr7_hehe

A dog searching for a bone walks 3.50m south, then 8.20m at angle 30.0o north of east and
finally 15m west. Using Graphical techniques, find the resultant displacement of dog.

Answers

Answered by Damon
Well you will have to draw the vectors. I can only do trig here.
North = -3.50 + 8.20 sin 30 = -3.5 + 4.1
East = 8.20 cos 30 - 15 = 8.2 * 0.866 - 15
magnitude = sqrt (North^2+East^2)
angle North of East = sin^-1 (North/East)
Watch out what quadrant you are in. (Quad II)
Answered by henry2,
D = -3.5i + 8.2*cos30+(8.2*sin30)i - 15
D = -3.5i+7.1+4.1i-15 = -7.9+0.6i
D = 7.92 m[-4.34o] = 7.92m[4.34o] W. of N.
Answered by alelgn
20
Answered by Andargachew
(-7.9i+0.6j)m

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