A dog searching for a bone walks 3.50m south, then 8.20m at angle 30.0o north of east and

Question

finally 15m west. Using Graphical techniques, find the resultant displacement of dog.

Answer 1

Well you will have to draw the vectors. I can only do trig here.
North = -3.50 + 8.20 sin 30 = -3.5 + 4.1
East = 8.20 cos 30 - 15 = 8.2 * 0.866 - 15
magnitude = sqrt (North^2+East^2)
angle North of East = sin^-1 (North/East)
Watch out what quadrant you are in. (Quad II)

Answer 2

D = -3.5i + 8.2*cos30+(8.2*sin30)i - 15
D = -3.5i+7.1+4.1i-15 = -7.9+0.6i
D = 7.92 m[-4.34o] = 7.92m[4.34o] W. of N.

Answer 3

20

Answer 4

(-7.9i+0.6j)m