Asked by Cunfushun
I don't understand how to solve the follow types of problems with exponets and fractions. If you explain with the examples provided that would be nice.
Ex. 1
4^-6 over 10
Ex. 2
6 over 9^-3
Ex. 1
4^-6 over 10
Ex. 2
6 over 9^-3
Answers
Answered by
Reiny
recall
x^-n = 1/x^2
then use the rules of regular fractions
I'll do the 2nd, you do the 1st in the same way:
6 over 9^-3
= 6/(9^-3)
but 9^-3 = 1/9^3 = 1/729
so 6/(9^-3) = 6 / (1/729)
= 6(729/1) = 4374
You can check these with your calculator, or google it
https://www.google.com/search?q=6%2F9%5E-3&rlz=1C5CHFA_enCA690CA690&oq=6%2F9%5E-3&aqs=chrome..69i57j6.6765j0j8&sourceid=chrome&ie=UTF-8
x^-n = 1/x^2
then use the rules of regular fractions
I'll do the 2nd, you do the 1st in the same way:
6 over 9^-3
= 6/(9^-3)
but 9^-3 = 1/9^3 = 1/729
so 6/(9^-3) = 6 / (1/729)
= 6(729/1) = 4374
You can check these with your calculator, or google it
https://www.google.com/search?q=6%2F9%5E-3&rlz=1C5CHFA_enCA690CA690&oq=6%2F9%5E-3&aqs=chrome..69i57j6.6765j0j8&sourceid=chrome&ie=UTF-8
Answered by
Cunfushun
Thank you!
Answered by
Cunfushun
So...
(4^-6)/10
4^-6 = 1/4^6 = 4096
(1/4096) /10
1/40960
Did I do that right?
(4^-6)/10
4^-6 = 1/4^6 = 4096
(1/4096) /10
1/40960
Did I do that right?
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