Asked by Chimcy
An electron is traveling at 2.3 *10^3m/s, enters perpendicular to the electric field between two horizontal charged parallel plates. If the electric field strength is 1.5*10^2V/m calculate the time taken for the electron to deflect a distance of 1.0*10^-2 toward the positive plate. Ans: 2.8*10^-8s
Answers
Answered by
Damon
speed << speed of light so forget special relativity
F = q E = 1.6*10^-19 * 1.5*10^2
a = F/m = 1.6 * 10^-19 * 1.5*10^2 / (9.1 * 10^-31)
= (1.6*1.5 / 9.1) * 10^14 m/s^2 = 0.264 * 10^14
d = (1/2) a t^2
10*-2 = 0.132 * 10^14 t^2
t^2 = (1/0.132) * 10^-16
t = sqrt(7.58) * 10^-8 = 2.75 *10^-8 seconds,
not long but it goes (2.3*10^3) (2.75*10^-8) = 6.3 * 10^-5 meters forward during that time
F = q E = 1.6*10^-19 * 1.5*10^2
a = F/m = 1.6 * 10^-19 * 1.5*10^2 / (9.1 * 10^-31)
= (1.6*1.5 / 9.1) * 10^14 m/s^2 = 0.264 * 10^14
d = (1/2) a t^2
10*-2 = 0.132 * 10^14 t^2
t^2 = (1/0.132) * 10^-16
t = sqrt(7.58) * 10^-8 = 2.75 *10^-8 seconds,
not long but it goes (2.3*10^3) (2.75*10^-8) = 6.3 * 10^-5 meters forward during that time
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.