Asked by ABC_ABC
One mole (mol) of any substance consists of 6.022 x 10²³ molecules
(Avogadro's number). What is the translational kinetic energy of 12.00mol of
an ideal gas at 290.0K?
(Avogadro's number). What is the translational kinetic energy of 12.00mol of
an ideal gas at 290.0K?
Answers
Answered by
DrBob222
https://www.softschools.com/formulas/physics/kinetic_energy_of_gas_formula/337/#:~:text=In%20an%20ideal%20gas%2C%20there,or%20vibration%20within%20the%20molecules.&text=using%20the%20formula%3A-,The%20average%20translational%20kinetic%20energy%20of%20a%20single%20molecule%20of,of%20molecules%20(Avogadro's%20number).
avg kinetic energy of ideal gas is 3/2 kT. k is Boltzman constant. T is in kelvin. This give you the avg KE per molecule. Multiply that by Avogadro's number x 12.
avg kinetic energy of ideal gas is 3/2 kT. k is Boltzman constant. T is in kelvin. This give you the avg KE per molecule. Multiply that by Avogadro's number x 12.
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