Asked by Jacqueline

Using the truth table, show that the following proposition is a contradiction.
negation of [((p → negation of q) ∧ q) → negation of p]

5 years ago

Answered by oobleck

so, did you build the truth table? What did you get?

5 years ago

Answered by Rohit

(p^q)^~q is contradiction

4 years ago

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