Asked by 123
How do I solve 6yx^2 +y-x-2xy^2?
Answers
Answered by
123
6yx^2 +y-x-2xy^2 =0
Answered by
oobleck
You can write this as a quadratic equation in x or y. If in x, then you have
6yx^2 - (1+2y^2)x + y = 0
Then just apply the quadratic formula to get the rather nasty result of
x = [(1+2y^2)±√(y^4-20y^2+1)] / 12y
or a similar ugly expression for y.
6yx^2 - (1+2y^2)x + y = 0
Then just apply the quadratic formula to get the rather nasty result of
x = [(1+2y^2)±√(y^4-20y^2+1)] / 12y
or a similar ugly expression for y.