Asked by Hasan
Calculate the weight of solid NaOH required to prepare (a) 5 liters of a 2 M solution, (b) 2 liters of a solution of pH 11.5?
Answers
Answered by
DrBob222
(a) How many mols do you want? That's mols = M x L = 2 x 5 = 10
Then grams = mols NaOH x molar mass NaOH = ?
(b) pH of 11.5 is a pOH of 2.5 (that's 14-11.5 = 2.5).
So (OH^-) in mols/L = -log(OH^-) = -log 2.5
OH^- = ? remember in mols/L. You want 2 L so mols you want will be M x L = ?
Then follow the first solution in a.
Then grams = mols NaOH x molar mass NaOH = ?
(b) pH of 11.5 is a pOH of 2.5 (that's 14-11.5 = 2.5).
So (OH^-) in mols/L = -log(OH^-) = -log 2.5
OH^- = ? remember in mols/L. You want 2 L so mols you want will be M x L = ?
Then follow the first solution in a.
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