Asked by Victoria
A solid weight 4.8g in air, 2.8g in water and 3.2 in kerosine calculate the relative density of the kerosine
Answers
Answered by
Victoria
show me how u solved it
Answered by
Damon
first find the volume
It displaced 4.8 - 2.8 = 2 grams of water
water has density of 1 gram/ cm^3
so its volume is 2 cm^3
in kerosene it displaces the same volume = 2 cm^3
however that 2 cm^2 weighs
4.8 - 3.2 = 1.6 grams
so kerosene s 1.6 grams / 2 cm^3 = 0.8 grams/cm^3 or 0.8 times water density
It displaced 4.8 - 2.8 = 2 grams of water
water has density of 1 gram/ cm^3
so its volume is 2 cm^3
in kerosene it displaces the same volume = 2 cm^3
however that 2 cm^2 weighs
4.8 - 3.2 = 1.6 grams
so kerosene s 1.6 grams / 2 cm^3 = 0.8 grams/cm^3 or 0.8 times water density
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