Ask a New Question

Asked by Anonymous

Find an equation of the tangent plane to the surface given by z = f (x,y )=𝑥^2 y + x𝑦^3 at the point (x,y)=(2,1).
5 years ago

Answers

Answered by oobleck
∂z/∂x = 2xy + y^3
∂z/∂y = x^2 + 3xy^2
z(2,1) = 4+2 = 6
So the tangent plane at (1,2) is
z-6 = 5(x-2) + 10(y-1)
5 years ago

Related Questions

Find an equation of the tangent plane (in the variables x, y and z) to the parametric surface r(u,... Find an equation of the tangent line to the curve at the given point. (Assume the tangent line form... Find the equation of tangent line to the curve Y=2/x^2+x At the point where x=1 Find an equation of the tangent line to the curve y=10^(x) at the point (1,10) Find the equation of tangent to the curve y=2x-x^3 at the point x=-1. Where does that tangent meet t...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use