Asked by Afra
calculate the slope of tangent to the given function at the given point
f(x) = 2 / √x+5 , P(4,2/3)
f(x) = 2 / √x+5 , P(4,2/3)
Answers
Answered by
Reiny
I assume you meant:
f(x) = 2/√(x+5) = 2(x+5)^(-1/2)
f ' (x) = -(x+5)^(-3/2)
at (4, 23)
f ' (4) = -(9)^(-3/2)
= -1/9^(3/2) = -1/27
tangent equation:
(y-2/3) = (-1/27)(x-4)
27y - 18 = -x + 4
x + 27y = 22
f(x) = 2/√(x+5) = 2(x+5)^(-1/2)
f ' (x) = -(x+5)^(-3/2)
at (4, 23)
f ' (4) = -(9)^(-3/2)
= -1/9^(3/2) = -1/27
tangent equation:
(y-2/3) = (-1/27)(x-4)
27y - 18 = -x + 4
x + 27y = 22
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.