Asked by Niz

A triangle has the length of AB = 125ft, BC = 85ft. The size if angle C is 63°. Determine the length of AC.
Answered by R_scott
use the law of sines to find ∠A (opposite BC)

subtract ∠C and ∠A from 180º to find ∠B (opposite AC)

use the law of sines (again) to find AC (opposite ∠B)
Answered by henry2,
sinA/85 = sin63/125
A = 37 degrees.

B = 180-37-63 = 80 degrees.

AC/sin80 = 125/sin63.
AC =
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