Asked by C

3. Find the length of the curve given by r(t)= √(2)ti +e^t j +e^-t k, 0≤t≤1.
Answered by oobleck
ds^2 = t^2 + e^2t + e^-2t = (e^t + e^-t)^2
ds = e^t + e^-t = 2cosh(t)
so the arc length is
∫[0,1] 2cosh(t) dt = 2sinh(t) [0,1] = 2sinh(1) = e - 1/e
Answered by C
ds = e^t + e^-t = 2cosh(t) what this mean? does it mean e^t +e^-t is the same ascosh(t)?
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